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CGP EDU Academic Team
Published on: September 12, 2026
A ball of mass 0.1 kg is suspended by a string. It is displaced through an angle of 60^\circ and left. When the ball passes through the mean position, the tension in the string is
Text Solution
Verified by ExpertsThe correct answer is:
B
\(T = mg + \frac{mv^{2}}{l}\) = \(mg + \frac{m}{l} \left[ 2gl(1 - \cos \theta) \right]\)
= \(mg + 2mg \left( 1 - \cos 60^\circ \right)\) = 2mg =2× 0.1 × 9.8=1.96 N
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